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Q.

A mass of 50 g of water in a closed vessel, with surroundings at a constant temperature takes 2 minutes to cool from 30°C to 25°C. A mass of 100 g of another liquid in an identical vessel with identical surroundings takes the same time to cool from 30°C to 25°C. The specific heat (in kcal/kg) of the liquid is :(The water equivalent of the vessel is 30 g.)

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answer is 0.5.

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Detailed Solution

As the surrounding is identical, vessel is identical . Time taken to cool both water and liquid (from 30°C to 25°C ) is same 2 minutes, thereforedQdtwater =dQdtliquid ​ or, mwCw+WΔTt=mlCl+WΔTt​ (W = water equivalent of the vessel) ​ or ,mwCW=mlCl​∴ Specific heat of liquid, Cl=mWCWml​=50×1100=0.5kcal/kg
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