A mass of $$10$$ gm moving with a velocity of $$100$$ $$cm/s$$ strikes a pendulum bob of mass $$10$$ gm. The two masses stick together. The maximum height (in$$ $$cm) reached by the system now is (g=10$$ $$m/s2)

Question

A mass of $$10$$ gm moving with a velocity of $$100$$ $$cm/s$$ strikes a pendulum bob of mass $$10$$ gm. The two masses stick together. The maximum height (in$$ $$cm) reached by the system now is (g=10$$ $$m/s2)

Infinity Learn · Accepted Answer

Initially mass $$10$$ gm  moves with velocity $$100$$ $$cm/s$$∴ Initial momentum $$=$$ $$10$$ × $$100$$ $$=$$ $$1000gm$$×msecAfter collision system moves with velocity vsys.  then Final momentum $$=$$  (10+10)×vsys.By applying the conservation of momentum $$10000=20$$×vsys.⇒vsys.$$=50$$ cm​$$/$$​sIf system rises upto height h then $$h=vsys.22g=50$$×$$502$$×$$1000=2.52=1.25$$ cm

Collisions

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A mass of 10 gm moving with a velocity of 100 cm/s strikes a pendulum bob of mass 10 gm. The two masses stick together. The maximum height (in cm) reached by the system now is $(g = 10 m / s^{2})$

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Collisions

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A mass of 10 gm moving with a velocity of 100 cm/s strikes a pendulum bob of mass 10 gm. The two masses stick together. The maximum height (in cm) reached by the system now is (g=10 m/s2)

Ready to Test Your Skills?

free study material

A mass of 10 gm moving with a velocity of 100 cm/s strikes a pendulum bob of mass 10 gm. The two masses stick together. The maximum height (in cm) reached by the system now is $(g = 10 m / s^{2})$