A mass of 1 kg is attached to the middle of a rope, which is being pulled from both the opposite directions. Taking g - 10 m/s2, what is the minimum pull required to completely straighten the rope ?

If A, B and C be three vectors acting at a point and their resultant is zero, thenAsin⁡α=Bsin⁡β=Csin⁡γwhere α,β and γ are shown in figure.To straighten the rope, λ should be 180°. Now α=β=90∘∴A=B=Csin⁡180=1×100=∞