A mass of $$0.98$$ kg attached to a spring of constant K $$=$$ $$100$$ $$Nm-1$$ is hit by a bullet of $$20$$ gm moving with a velocity $$30$$ $$ms-1$$ horizontally. The bullet gets embedded and the system oscillates with the mass on horizontal friction less surface. The amplitude of oscillations will be

Question

A mass of $$0.98$$ kg attached to a spring of constant K $$=$$ $$100$$ $$Nm-1$$ is hit by a bullet of $$20$$ gm moving with a velocity $$30$$ $$ms-1$$ horizontally. The bullet gets embedded and the system oscillates with the mass on horizontal friction less surface. The amplitude of oscillations will be

Infinity Learn · Accepted Answer

Conservation of $$momentum(0.98+0.02)v$$ $$=$$ $$0.02$$× $$30$$ ⇒ v $$=$$ $$0.6$$ $$ms-1Conserving$$ energy in oscillation we $$get12(0.98+0.02)v2=$$ $$12KA2$$∴  $$A2$$ $$=$$ $$v2K=$$ $$(0.6)2100$$   ⇒A $$=$$ $$0.610$$ $$=$$ $$0.06$$ m $$=$$ $$6$$ cm

A mass of 0.98 kg attached to a spring of constant K = 100 N $m^{- 1}$ is hit by a bullet of 20 gm moving with a velocity 30 ${ms}^{- 1}$ horizontally. The bullet gets embedded and the system oscillates with the mass on horizontal friction less surface. The amplitude of oscillations will be

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

A mass of 0.98 kg attached to a spring of constant K = 100 Nm-1 is hit by a bullet of 20 gm moving with a velocity 30 ms-1 horizontally. The bullet gets embedded and the system oscillates with the mass on horizontal friction less surface. The amplitude of oscillations will be

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

A mass of 0.98 kg attached to a spring of constant K = 100 N $m^{- 1}$ is hit by a bullet of 20 gm moving with a velocity 30 ${ms}^{- 1}$ horizontally. The bullet gets embedded and the system oscillates with the mass on horizontal friction less surface. The amplitude of oscillations will be