Q.

A mass 10kg moving with a speed 10 cm/s on a smooth horizontal surface hits a spring as shown in figure.  Work done by the spring force on the mass is ,

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a

0.05 J

b

-0.05 J

c

-0.1 J

d

0.1 J

answer is B.

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Detailed Solution

from work energy theorem work done = change in KE W = KEfinal-KEinitial; mass comes to rest finally , KEfinal=0 Work done by spring  =   - K.E. of mass work done=    −12(10)  (0.1)2  work done by spring  =    −  0.05 joule
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