Q.
A mass 10kg moving with a speed 10 cm/s on a smooth horizontal surface hits a spring as shown in figure. Work done by the spring force on the mass is ,
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a
0.05 J
b
-0.05 J
c
-0.1 J
d
0.1 J
answer is B.
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Detailed Solution
from work energy theorem work done = change in KE W = KEfinal-KEinitial; mass comes to rest finally , KEfinal=0 Work done by spring = - K.E. of mass work done= −12(10) (0.1)2 work done by spring = − 0.05 joule
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