A mass 10kg moving with a speed 10 cm/s on a smooth horizontal surface hits a spring as shown in figure. Work done by the spring force on the mass is ,
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
0.05 J
b
-0.05 J
c
-0.1 J
d
0.1 J
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
from work energy theorem work done = change in KE W = KEfinal-KEinitial; mass comes to rest finally , KEfinal=0 Work done by spring = - K.E. of mass work done= −12(10) (0.1)2 work done by spring = − 0.05 joule