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A mass of 2.0 kg is put on a flat pan attached to a vertical spring fixed on the ground as shown in the figure. The mass of the spring and the pan is negligible. When pressed slightly and released the mass executes a simple harmonic motion. The spring constant is 200 N/m. What should be the minimum amplitude of the motion, so that the mass gets detached from the pan? (Take g = l0 m/s2)

a
8.0 cm
b
10.0 cm
c
Any value less than 12.0 cm
d
4.0 cm

detailed solution

Correct option is B

Let the minimum amplitude of SHM is a.Restoring force on spring, F = kaRestoring force is balanced by weight mg of block.For mass to execute simple harmonic motion of amplitude a.ka = mg or a = mgkHere, m = 2 kg, k = 200 N/m, g = l0 m/s2a = 2×10200 = 10100m = 10100×100 cm = 10 cmHence, minimum amplitude of the motion should be l0 cm, so that the mass gets detached from the pan.

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