A mass of $$4$$ kg is suspended by a rope of length $$4$$ m from a ceiling. A force of $$20$$ N in the horizontal direction is applied at the $$mid-point$$ of the rope as shown in figure. What is the angle which the rope makes with the vertical in equilibrium? Neglect the mass of the rope. Take g $$=$$ $$l0$$ $$ms-2$$

Question

A mass of $$4$$ kg is suspended by a rope of length $$4$$ m from a ceiling. A force of $$20$$ N in the horizontal direction is applied at the $$mid-point$$ of the rope as shown in figure. What is the angle which the rope makes with the vertical in equilibrium? Neglect the mass of the rope. Take g $$=$$ $$l0$$ $$ms-2$$

Infinity Learn · Accepted Answer

$$T2$$ $$=$$ mg $$=$$ $$4$$ × $$10$$ $$=$$ $$40$$ $$NT1$$ $$cos$$ θ $$=$$ $$40$$; $$T1$$ $$sin$$ θ $$=$$ $$20$$ $$tan$$ θ $$=$$ $$12$$  ⇒ θ $$=$$ $$tan$$$$-1(12)$$

A mass of 4 kg is suspended by a rope of length 4 m from a ceiling. A force of 20 N in the horizontal direction is applied at the mid-point of the rope as shown in figure. What is the angle which the rope makes with the vertical in equilibrium? Neglect the mass of the rope. Take g = l0 ${ms}^{- 2}$

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A mass of 4 kg is suspended by a rope of length 4 m from a ceiling. A force of 20 N in the horizontal direction is applied at the mid-point of the rope as shown in figure. What is the angle which the rope makes with the vertical in equilibrium? Neglect the mass of the rope. Take g = l0 ms-2

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A mass of 4 kg is suspended by a rope of length 4 m from a ceiling. A force of 20 N in the horizontal direction is applied at the mid-point of the rope as shown in figure. What is the angle which the rope makes with the vertical in equilibrium? Neglect the mass of the rope. Take g = l0 ${ms}^{- 2}$