A mass of 4 kg is suspended by a rope of length 4 m from a ceiling. A force of 20 N in the horizontal direction is applied at the mid-point of the rope as shown in figure. What is the angle which the rope makes with the vertical in equilibrium? Neglect the mass of the rope. Take g = l0 ms-2

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tan-12

tan-1(12)

tan-12

tan-1(12)

answer is B.

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Detailed Solution

T2 = mg = 4 × 10 = 40 NT1 cos θ = 40; T1 sin θ = 20 tan θ = 12 ⇒ θ = tan-1(12)

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