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Q.

A  mass of 10 kg is suspended by a rope of length 4m, from the ceiling. A force F is applied horizontally at the mid-point of the rope such that the top half of the rope makes an angle of 45º with the vertical. Then F equals: (Take g = 10 ms-2 and the rope to be massless)

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a

100N

b

90N

c

75N

d

70N

answer is A.

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Detailed Solution

Tcos45o = mg ⇒T2=100   ......(1)Tsin45o=F ⇒T2=F             ⇒ F=100N   [from equation (1)]
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