Questions
A mass of 10 kg is suspended by a rope of length 4m, from the ceiling. A force F is applied horizontally at the mid-point of the rope such that the top half of the rope makes an angle of 45º with the vertical. Then F equals: (Take g = and the rope to be massless)
detailed solution
Correct option is A
Tcos45o = mg ⇒T2=100 ......(1)Tsin45o=F ⇒T2=F ⇒ F=100N [from equation (1)]Talk to our academic expert!
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Natural length of the spring is 40 cm and its spring constant is 4000 N m-1. A mass of 20 kg is hung from it. The extension produced in the spring is (Given g = 9.8 m s-2)
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