The mass and length of a wire are M and L respectively. The density of the material of the wire is d. On applying the force F on the wire, the increase in length is l, then the Young's modulus of the material of the wire will be
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a
FdlMl
b
FLMdl
c
FMldl
d
FdL2Ml
answer is D.
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Detailed Solution
Y = FALl = FdL2MlAs M = volume ×density = A × L ×d∴ A = MLd