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Q.

The mass and length of a wire are M and Z, respectively. The density of the material of the wire is d. On applying the force F on the wire, the increase in length is l. Then the Young's modulus of the material of the wire will be

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a

FdlMl

b

FLMdl

c

FMldl

d

FdL2Ml

answer is D.

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Detailed Solution

Y=FLAl=FdL2Ml As M= Volume × Density =A×L×d⇒A=MLd
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