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A mass ‘M’ is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes SHM of time period ‘T, if the mass is increased by ‘m’, time period becomes \large \frac{{5T}}{3}, then the ratio of (m / M ) is

a
b
c
d

detailed solution

Correct option is C

25 M = 9 M + 9 m  16M = 9m

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