First slide
Simple hormonic motion
Question

 A mass m is attached to four springs of spring constants 2.k,2k,-k and k as shown in fig. (2). The mass
 

s capable of oscillating on friction less horizontal floor. If it is displaced slightly and released then the frequency of resulting S.H.M. would be

Easy
Solution

 The resultant force constant is given by 
k=(2k)(2k)2k+2k+(k+k)=3k
We know that
T=2πmk=2πm3k Now n=1T=12π3km 

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