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A mass M attached to a spring oscillates with a period of 1s. If the mass is increased by 3 kg, the assuming that Hookes’ law is obeyed. The period increases by 1s. Find the value of M (in kg)

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Detailed Solution

1=2πMk and 2=2πM+3k Dividing these quations we get 4=M+3M⇒M=1 kg

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