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Q.

A mass m = 20 g has a charge q = 3.0mC. It moves with a velocity of 20 m/s and enters a region of electric field of 80 N/C in the same direction as the velocity of the mass. The velocity of the mass after 3 seconds in this region is

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a

80 m/s

b

56 m/s

c

44 m/s

d

40 m/s

answer is B.

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Detailed Solution

a=QEm=3×10−3×8020×10−3=12m/sec2Hence v=u+at⇒v=20+12×3=56 m/s
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