First slide

Electrostatic potential energy

Question

A mass m = 20 g has a charge q = 3.0mC. It moves with a velocity of 20 m/s and enters a region of electric field of 80 N/C in the same direction as the velocity of the mass. The velocity of the mass after 3 seconds in this region is

Easy

A

80 m/s
B

56 m/s
C

44 m/s
D

40 m/s

Solution

$a = \frac{QE}{m} = \frac{3 \times 10^{- 3} \times 80}{20 \times 10^{- 3}} = 12 m / \sec^{2}$
Hence $v = u + at \Rightarrow v = 20 + 12 \times 3 = 56 m / s$

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