A mass m =100 gms is attached at the end of a light spring which oscillates on a frictionless horizontal table with an amplitude equal to 0.16 metre and time period equal to 2 sec. Initially the mass is released from rest at t = 0 and displacement x=−0.16 metre. The expression for the displacement of the mass at any time t is

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x=0.16cos(πt)

x=− 0.16cos(πt)

x=0.16sin(πt+π)

x=− 0.16sin(πt+π)

answer is B.

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Detailed Solution

Standard equation for given condition x=acos2πTt⇒x=−0.16cos(π t)[As a = – 0.16 meter, T = 2 sec]

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