Questions
A mass M is hung with a light inextensible string as shown in the figure. Find the tension of the horizontal string.
detailed solution
Correct option is B
As there is a load at P, so tension in AP and PB will be different. Let these be T2 and T1, respectively. For vertical equilibrium at P,T1cos60°=Mg, i.e. T1=2Mg .......(i)and for horizontal equilibrium at P,T2 = T1 sin 600 = T1 (3/2)Substituting the value of T1 from Eq. (i), we getT2=(2Mg)×(3/2)=3MgTalk to our academic expert!
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A uniform sphere of weight W and radius 3 m is being held by a string of length 2m.attached to a frictionless wall as shown in the t figure. The tension in the string will be:
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