A mass of M kg is suspended by a weight less string the horizontal force that requires to displace it until the string making an angle $$45$$° with the initial vertical direction is

Question

A mass of M kg  is suspended by a weight less string the horizontal force that requires to displace it until the string making an angle $$45$$° with the initial vertical direction is

Infinity Learn · Accepted Answer

work done by horizontal force is $$W=$$ F×ℓ $$sin45$$°            Work done by horizontal force $$=F$$ℓ$$2---------(1)$$          gain in $$PE$$ of pendulum $$=$$ Mgh $$PE$$$$=Mg($$ℓ−ℓ $$cos45$$°$$)$$ $$PE$$$$=Mg$$ℓ(1-12)             $$PE$$ $$=Mg$$ℓ  (2$$−$$12)-----------(2)        substitute equation (1) in (2) ∴   Fℓ$$2$$  $$=$$   Mgℓ(2$$−$$12)        ⇒     F    $$=$$    Mg (2$$−$$1)

A mass of M kg is suspended by a weight less string the horizontal force that requires to displace it until the string making an angle 45° with the initial vertical direction is

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