A mass of M kg is suspended by a weightless string. The horizontal force that is required to displace it until the string makes an angle of $$450$$ with the initial vertical direction is

Question

Infinity Learn · Accepted Answer

The situation is shown in fig. (9)The$$ constant force F required to take the body from position $$1$$ to position $$2$$ can be calculated by applying $$work-energy$$ theorem. We assume that the body is taken slowly so that its speed doesn't change, i.e.Δ$$K=0WF+WMg+Wtension$$ $$=0$$ Hero  $$WF=F$$×lsin⁡$$45$$∘ $$WMg=Mgl$$−lcos⁡$$45$$∘ Wtension $$=0$$ F×lsin⁡$$45$$∘$$+Mgl$$−lcos⁡$$45$$∘$$=0$$ or $$F=Mg(2$$−$$1)

A mass of M kg is suspended by a weightless string. The horizontal force that is required to displace it until the string makes an angle of 45⁰ with the initial vertical direction is

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A mass of M kg is suspended by a weightless string. The horizontal force that is required to displace it until the string makes an angle of 450 with the initial vertical direction is

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A mass of M kg is suspended by a weightless string. The horizontal force that is required to displace it until the string makes an angle of 45⁰ with the initial vertical direction is