A mass of M kg suspended by a weightless string and a horizontal force that is applied to displace the mass until the string makes an angle of 45 with the initial vertical direction. Find the force
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a
Mg(2+1)
b
Mg2
c
Mg2
d
Mg(2−1)
answer is D.
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Detailed Solution
Here, the constant horizontal force required to take the body from position 1 to position 2 can be calculated by using work energy theorem. Let us assume that body taken slowly so that its speed doesn't change, then ΔK = 0=WF+WMg+Wtension (symbols have their usual meanings)WF=F×lsin45∘,WMg= -Mgl−lcos45∘,Wtension =0∴F=Mg(2−1)