A mass M of 100 kg is suspended with the use of strings A, B and C as shown in fig. Here W is vertical wall and of is rigid horizontal rod. The tension in string B is

Let T be the tension in the string C. ThenT cos⁡45∘=Mg   â€¦(1)and T sin⁡45∘= tension in B   â€¦(2)From eq. (i),  T=Mgcos⁡45∘=2MgFrom eq. (ii), tension in B=Tsin⁡45∘=(2Mg)×(1/2)=Mg=100g newton.