Q.
A mass M of 100 kg is suspended with the use of strings A, B and C as shown in fig. Here W is vertical wall and of is rigid horizontal rod. The tension in string B is
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a
(100 g)N
b
(100 â2 g)N
c
(100/â2 Ã g)N
d
zero
answer is A.
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Detailed Solution
Let T be the tension in the string C. ThenT cosâ¡45â=Mg â¦(1)and T sinâ¡45â= tension in B â¦(2)From eq. (i), T=Mgcosâ¡45â=2MgFrom eq. (ii), tension in B=Tsinâ¡45â=(2Mg)Ã(1/2)=Mg=100g newton.
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