Questions
A mass m moves with a velocity v and collides elastically with another identical mass. After collision the first mass moves with velocity v / direction perpendicular to the initial direction of motion. Find the speed of the second mass after collision
detailed solution
Correct option is C
In x-directionmv1+0=0+mvx or vx=v1=v In y-direction 0+0=mv3+mvy or vy=v3 ∴ Velocity of second mass after collision v′=v32+v2=43v2=23vTalk to our academic expert!
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Two spheres A and B of masses m1 and m2 respectively collide. A is at rest initially and B is moving with velocity v along X-axis. After collision, B has a velocity v/2 in a direction perpendicular to the original direction. The mass A moves after collision in the direction
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