A mass m moves with a velocity v and collides elastically with another identical mass. After collision the first mass moves with velocity v /3 direction perpendicular to the initial direction of motion. Find the speed of the second mass after collision

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23v

answer is C.

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Detailed Solution

In x-directionmv1+0=0+mvx or vx=v1=v In y-direction 0+0=mv3+mvy or vy=v3 ∴ Velocity of second mass after collision v′=v32+v2=43v2=23v

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