Questions
A mass 'm' moves with a velocity 'v' and collides inelastically with another identical mass. After collision the Ist mass moves with velocity in a direction perpendicular to the initial direction of motion. Find the speed of the 2nd mass after collision
detailed solution
Correct option is A
Let mass A moves with velocity v and collides inelastically with mass B, which is at rest. According to problem mass A moves in a perpendicular direction and let the mass B moves at angle θ with the horizontal with velocity v. Initial horizontal momentum of system(before collision) = mv ....(i)Final horizontal momentum of system (after collision) = mV cosθ ....(ii)From the conservation of horizontal linear momentum mv = mV cosθ ⇒ v = V cosθ ...(iii)Initial vertical momentum of system (before collision) is zero.Final vertical momentum of system mv3−mVsinθFrom the conservation of vertical linear momentum mv3−mVsinθ=0⇒v3=Vsinθ ...(iv)By solving (iii) and (iv) v2+v23=V2(sin2θ+cos2θ)⇒4v23=V2 ⇒V=23vSimilar Questions
A sphere collides with another sphere of identical mass. After collision, the two spheres move. The collision is inelastic. Then the angle between the directions of the two spheres is
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