A mass m oscillates with simple harmonic motion with frequency f=ω2π and amplitude A on a spring with constant K , therefore

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The total energy of the system is 12KA2

The frequency is 12πKM

The maximum velocity occurs, when x = 0

All the above are correct

answer is D.

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Detailed Solution

Total energy is given by 12KA2. time period and frequency are T=2πMK and f=12πKMVelocity is max at mean position (x=0) and min (x=A)

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