A mass $$2m$$ rests on a horizontal table. It is attached to light inextensible string which passes over a smooth pulley and carries a mass m at the other end. If the mass m is raised vertically through a distance h and is then dropped then the speed with which the mass $$2m$$ begins to rises is $$2ghN$$ then ‘N’ is equal $$to_______$$

Question

A mass $$2m$$ rests on a horizontal table. It is attached  to light inextensible string which passes over a smooth pulley and carries a  mass m at the  other end. If the mass m  is raised vertically through a distance h and is then dropped then the speed  with which the mass $$2m$$ begins to rises is $$2ghN$$      then ‘N’ is  equal $$to_______$$

Infinity Learn · Accepted Answer

Let J be the impulse (or$$ $$jerk) and v the common speed.  Applying   $$Impluse=change$$ in linear momentumFor mass m,$$J=mv0$$−mv     $$J=2mv$$     $$V=2gh3$$

Application of Newtons laws

Remember concepts with our Masterclasses.

Let J be the impulse (or jerk) and v the common speed. Applying
Impluse=change in linear momentum

For mass m,

$J = m v_{0} - m v$

$J = 2 m v$

$V = \frac{\sqrt{2 g h}}{3}$

Ready to Test Your Skills?

free study material

Application of Newtons laws

Remember concepts with our Masterclasses.

Let J be the impulse (or jerk) and v the common speed. Applying Impluse=change in linear momentum For mass m, J=mv0−mv J=2mv V=2gh3

Ready to Test Your Skills?

free study material

Let J be the impulse (or jerk) and v the common speed. Applying
Impluse=change in linear momentum

For mass m,

$J = m v_{0} - m v$

$J = 2 m v$

$V = \frac{\sqrt{2 g h}}{3}$