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Q.

A mass m is suspended by means of two coiled springs which have the same length in unstretched condition fig.  Their force constants are k1 and k2 k1 and k2  respectively. When set into vertical vibrations, the period will be

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a

2πmk1k2

b

2πmk1k2

c

2πmk1−k2

d

2πmk1+k2

answer is D.

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Detailed Solution

When the springs are connected in parallel, the spring constant  k=k1+k2 ∴ T=2πmk=2πmk1+k2
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