A mass M is suspended by a rope from a rigid support at A as shown in fig. Another rope istied at the end 8, and it is pulled horizontally with a force F. If the rope AB makes an angle q with the vedical, then the tension in the string AB is
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a
Fsinq
b
F/sinq
c
Fcosq
d
F/cosq
answer is B.
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Detailed Solution
Different forces are shown in fig. In fig., the point I is in equilibrium under the action of X, F and Mg. HereT=AB=CB/sinθ=F/sinθ or F=TsinθAlso, T=AB=AC/cosθ=Mg/cosθ or Mg=Tcosθ∴ T2=F2+(Mg)2 or T=F2+(Mg)21/2.