A mass M is suspended by two springs of force constants K1 and K2 respectively as shown in the diagram. The total elongation (stretch) of the two springs is
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a
MgK1+K2
b
Mg (K1+K2)K1K2
c
Mg K1K2K1+K2
d
K1+K2K1K2Mg
answer is B.
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Detailed Solution
For series combination keq=k1k2k1+k2F=keqx⇒mg=k1k2k1+k2x⇒x=mg(k1+k2)k1k2