A mass M is suspended from a light spring. An additional mass m added displaces the spring further by a distance x. Now the combined mass will oscillate on the spring with period
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a
T=2πmg/x(M+m)
b
T=2π(M+m)x/mg
c
T=(π/2)mg/x(M+m)
d
T=2π(M+m)/mgx
answer is B.
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Detailed Solution
As mg produces extension x, hence k=mgx∴T=2π(M+m)k=2π(M+m)xmg