A mass m is suspended from a spring of length l and force constant K. The frequency of vibration of the mass is $$f1$$ . The spring is cut into two equal parts and the same mass is suspended from one of the parts. The new frequency of vibration of mass is $$f2$$ . Which of the following relations between the frequencies is correct

Question

Infinity Learn · Accepted Answer

When spring is cut into two equal parts then spring constant of each part will be $$2K$$ and so using n∝K, new frequency will be $$2$$  times i.e. $$f2=2$$ $$f1$$ .

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