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A mass m is suspended from a spring of length l and force constant K. The frequency of vibration of the mass is f1 . The spring is cut into two equal parts and the same mass is suspended from one of the parts. The new frequency of vibration of mass is f2 . Which of the following relations between the frequencies is correct

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a

f1=2f2

b

f1=f2

c

f1=2f2

d

f2=2f1

answer is D.

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Detailed Solution

When spring is cut into two equal parts then spring constant of each part will be 2K and so using n∝K, new frequency will be 2  times i.e. f2=2 f1 .
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A mass m is suspended from a spring of length l and force constant K. The frequency of vibration of the mass is f1 . The spring is cut into two equal parts and the same mass is suspended from one of the parts. The new frequency of vibration of mass is f2 . Which of the following relations between the frequencies is correct