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Q.

A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes simple harmonic oscillations with a time period T. If the mass is increased by m then the time period becomes  54T. The ratio of mM  is

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a

9/16

b

25/16

c

4/5

d

5/4

answer is A.

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Detailed Solution

T=2πmK⇒m∝T2⇒m2m1=T22T12⇒M+mM=54TT2⇒mM=916
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