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A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes simple harmonic oscillations with a time period T. If the mass is increased by m then the time period becomes . The ratio of is
detailed solution
Correct option is A
T=2πmK⇒m∝T2⇒m2m1=T22T12⇒M+mM=54TT2⇒mM=916Talk to our academic expert!
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