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Q.

A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes simple harmonic oscillations with a time period T. If the mass is increased by m then the time period becomes(54T). The ratio of mM is

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a

916

b

2516

c

45

d

54

answer is A.

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Detailed Solution

T = 2πmK    ⇒m ∝T2  ⇒ m2m1 = T22T21⇒ M+mM = (54TT)2  ⇒ mM = 916
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A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes simple harmonic oscillations with a time period T. If the mass is increased by m then the time period becomes(54T). The ratio of mM is