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A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes SHM of time period T. If the mass is increased by m, the time period becomes, $\frac{5 T}{3}$ ,then the ratio of $\frac{m}{M}$ is :

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detailed solution

Correct option is C

T∝M⇒3T=M+mM⇒259=M+mM⇒mM=169

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A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes SHM of time period T. If the mass is increased by m, the time period becomes, 5T3,then the ratio of mMis :

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Ready to Test Your Skills?

free study material

A mass M is suspended from a spring of negligible mass. The spring is pulled a little and then released so that the mass executes SHM of time period T. If the mass is increased by m, the time period becomes, $\frac{5 T}{3}$ ,then the ratio of $\frac{m}{M}$ is :