First slide

Applications of SHM

Question

A mass m is suspended from the two coupled springs connected in series. The force constant for springs are $K_{1}$ and $K_{2}$ . The time period of the suspended mass will be

Moderate

A

$T = 2 π \sqrt{(\frac{m}{K_{1} + K_{2}})}$
B

$T = 2 π \sqrt{(\frac{m}{K_{1} - K_{2}})}$
C

$T = 2 π \sqrt{(\frac{m (K_{1} + K_{2})}{K_{1} K_{2}})}$
D

$T = 2 π \sqrt{(\frac{{mK}_{1} K_{2}}{K_{1} + K_{2}})}$

Solution

In series $k_{eq} = \frac{k_{1} k_{2}}{k_{1} + k_{2}}$ so time period $T = 2 π \sqrt{\frac{m (k_{1} + k_{2})}{k_{1} k_{2}}}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App