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A mass m is suspended separately by two different springs of spring constant K1 and K2 gives the time-period  t1 and  t2 respectively. If same mass m is connected by both springs as shown in figure then time-period t is given by the relation

a
t=t1+t2
b
t=t1.t2t1+t2
c
t2=t12+t22
d
t−2=t1−2+t2−2

detailed solution

Correct option is D

t1=2πmK1 and  t2=2πmK2Equivalent spring constant for shown combination is K1 + K2. So time period t is given by  t=2πmK1+K2By solving these equations we get  t−2=t1−2+t2−2

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