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Q.

A mass m is suspended separately by two different springs of spring constant K1 and K2 gives the time-period t1 and t2 respectively. If same mass m is connected by both springs as shown in figure then time-period t is given by the relation

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a

t=t1+t2

b

t=t1.t2t1+t2

c

t2=t12+t22

d

t−2=t1−2+t2−2

answer is D.

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Detailed Solution

t1=2πmK1 and t2=2πmK2Equivalent spring constant for shown combination is K1 + K2. So time period t is given by t=2πmK1+K2By solving these equations we get t−2=t1−2+t2−2

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