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Q.

A mass m is suspended separately by two different springs of spring constant K1 and K2 gives the time period t1 and t2 respectively. If the same mass m is connected by both springs as shown in the figure, then time period t is given by the relation

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a

t = t1+t2

b

t = t1t2t1+t2

c

t2 = t12+t22

d

t-2 = t1-2+t2-2

answer is D.

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Detailed Solution

t1 = 2πmK1 and t2 = 2πmK2Equivalent spring constant for shown combination is K1 + K2. So time period t is given by t = 2πmK1+K2By solving these equations we get t-2 = t1-2+t2-2
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