A mass m is suspended separately by two different springs of spring constant $K_{1} and K_{2}$ gives the time period $t_{1} and t_{2}$ respectively. If the same mass m is connected by both springs as shown in the figure, then time period t is given by the relation

Question

Infinity Learn · Accepted Answer

$$t1$$ $$=$$ $$2$$$$π$$$$mK1$$ and $$t2$$ $$=$$ $$2$$$$π$$$$mK2Equivalent$$ spring constant for shown combination is $$K1$$ $$+$$ $$K2$$. So time period t is given by t $$=$$ $$2$$$$π$$$$mK1+K2By$$ solving these equations we get $$t-2$$ $$=$$ $$t1-2+t2-2$$

A mass m is suspended separately by two different springs of spring constant $K_{1} and K_{2}$ gives the time period $t_{1} and t_{2}$ respectively. If the same mass m is connected by both springs as shown in the figure, then time period t is given by the relation

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A mass m is suspended separately by two different springs of spring constant K1 and K2 gives the time period t1 and t2 respectively. If the same mass m is connected by both springs as shown in the figure, then time period t is given by the relation

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A mass m is suspended separately by two different springs of spring constant $K_{1} and K_{2}$ gives the time period $t_{1} and t_{2}$ respectively. If the same mass m is connected by both springs as shown in the figure, then time period t is given by the relation