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Mass of moon is $7 \cdot 34 \times 10^{22} kg$ If the acceleration due to gravity on the moon is $1 \cdot 4 m / s^{2}$ the radius of the moon is $(G = 6 \cdot 667 \times 10^{- 11} {Nm}^{2} / {kg}^{2})$

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0.56 x 104m

1.87x106m

1.92 x 106 m

1.01x108m

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detailed solution

Correct option is B

We know that g =GM/R2∴ R=GM/g=6⋅667×10−117⋅34×10221.4=1⋅87×106m

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Mass of moon is 7⋅34×1022kg If the acceleration due to gravity on the moon is 1⋅4m/s2 the radius of the moon is G=6⋅667×10−11Nm2/kg2

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

Mass of moon is $7 \cdot 34 \times 10^{22} kg$ If the acceleration due to gravity on the moon is $1 \cdot 4 m / s^{2}$ the radius of the moon is $(G = 6 \cdot 667 \times 10^{- 11} {Nm}^{2} / {kg}^{2})$