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Q.

Mass of moon is (1/81) times that of earth and its radius is (1/4) as the radius of the earth' If the value of escape velocity at the surface of earth is 11 ' 2 km,/sec, its value at the surface of moon is

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a

0.14km/sec

b

0.5 km/sec

c

2.5km/sec

d

5km/sec

answer is C.

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Detailed Solution

The escape velocity is given byve=2GMR1/2For earth,11⋅2=2GMeRe1/2………..(1)For moon, vm=2GMe/81Re/41/2……(2)From eq. (2),vm=292GMeRe1/2=29×11⋅2=2⋅5km/sec
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