Questions
The mass of neutron and proton are 1.0087 amu and 1.0073 amu respectively and if two protons and two neutrons form a nucleus of helium whose mass is 4.0015 amu, Then find the binding energy of helium nucleus.
a
7.1 Mev
b
28.4 ev
c
28.4 Mev
d
26.2 Mev
detailed solution
Correct option is C
Binding energy=[2(1.0087+1.0073)−4.0015]×931.5 Mev =28.41 MevTalk to our academic expert!
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