In a mass spectrometer used for measuring the masses of ions, the ions are initially accelerated by an electric potential V and then made to describe semicircular paths of radius R using a magnetic field B. If V and B are kept constant, the ratio charge on the ion mass of the ion will be proportional to
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a
1/R
b
R
c
R2
d
1/R2
answer is D.
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Detailed Solution
The radius of the orbit in which ions movingR=mvqBThe angular frequency of rotation of the ions about the vertical field B is given byω=vR=qBm=2πvwhere v is frequency.Energy of ion is given byE=12mv2=12m(Rω)2=12mR2B2q2m2or E=12R2B2q2m ... (i)If ions are accelerated by electric potential V, then energy attained by ionsE = qV ... (ii)qV=12R2B2q2mor qm=2VR2B2If V and B are kept constant, then qm∝1R2