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A mass is suspended separately by two different springs in successive order, then time period is T1 and T2 respectively.If it is connected by both springs as shown in Fig. then time period is T0. The correct relation is
 

a
T02=T12+T22
b
T0-2=T1-2+T2-2
c
T0-1=T1-1+T2-1
d
T0=T1+T2

detailed solution

Correct option is B

T=2πmk⇒k∝1T2In parallel combination, k=k1+k2 1T02=1T12+1T22

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