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Masses each 1 kg are placed at the vertices of an isosceles triangle ABC in which AC=BC=10 cm and AB=16 cm. The distance of centre of mass of the system from the vertex C is

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a

2 cm

b

4 cm

c

1.5 cm

d

3 cm

answer is B.

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Detailed Solution

x=m2dm1+m2=2×623=4cm

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