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Masses each 1 kg are placed at the vertices of an isosceles triangle ABC in which $A C = B C = 10 c m$ and $A B = 16 c m .$ The distance of centre of mass of the system from the vertex C is

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detailed solution

Correct option is B

x=m2dm1+m2=2×623=4cm

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Masses each 1 kg are placed at the vertices of an isosceles triangle ABC in which AC=BC=10 cm and AB=16 cm. The distance of centre of mass of the system from the vertex C is

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Masses each 1 kg are placed at the vertices of an isosceles triangle ABC in which $A C = B C = 10 c m$ and $A B = 16 c m .$ The distance of centre of mass of the system from the vertex C is