The masses, each of mass m are kept on the vertices of an equilateral triangle of side a. Find the work needed to be done to change the length of each side of the triangle twice of its original value.

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Gm23a

−3Gm2a

3Gm22a

−3Gm22a

answer is C.

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Detailed Solution

By the work-energy theorem we can write thatWext+Wgr=Δ(K.E)=0⇒Wext=−Wgr=−(−ΔU)=ΔUWext=−3Gm22a−(−3Gm2a)=3Gm22a

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