The masses of neutron and proton are 1.0087amu and 1.0073 amu respectively. If the neutrons and protons combine to form helium nucleus of mass 4.0015 amu the binding energy of the helium nucleus will be
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a
29.4 MeV
b
20.8 MeV
c
27.3 MeV
d
14.MeV
answer is A.
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Detailed Solution
alpha paritcle He has 2 protons and 2 neutrons and their masses are 242x1.0078 and 2 x1.0087 total mass of 4.033 amu mass defect= 0.0315amu binding energy=0.0315x931.5 MeV=29.4 MeV