Masses of three wires are in the ratio 1:3:5. Their lengths are in the ratio 5:3:1. When connected in series with a battery, the ratio of heat produced in them will be
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a
125:15: 1
b
1: 15: 125
c
15:1:125
d
5: 9 : 5
answer is B.
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Detailed Solution
We know that , H=i2R∴ H=i2(ρl/A)=i2ρl2dmor H∝l2/mor H1:H2:H3=(5)21:(3)23:(1)25or H1:H2:H3=125:15:1Note. when they are connected in parallel, thenH=V2/R or H∝m/l2∴ H1:H2:H3=1:15:125