The masses of the three wires of copper are in the ratio 1 : 3 : 5. And their lengths are in the ratio 5 : 3 : 1. The ratio of their electrical resistance is

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1 : 3 : 5

5 : 3 : 1

1 : 15 : 125

125 : 15 : 1

answer is D.

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Detailed Solution

R=ρlA=ρl2Al=ρl2V=ρl2m/d=ρdl2m or R∝l2mR1:R2:R3=l12m1:l22m2:l32m3=251:93:15=125:15:1

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