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Masses of 3 wires of same metal are in the ratio 1 : 2 : 3 and their lengths are in the ratio 3 : 2 : 1. The electrical resistances are in the ratio

a
1 : 4 : 9
b
9 : 4 : 1
c
1 : 2 : 3
d
27 : 6 : 1

detailed solution

Correct option is D

R ∝ l2m  ⇒   R1  :  R2  :  R3 =   l12m1  :   l22m2  :  l32m3⇒   R1  :  R2  :  R3 =  91  :  42  :  13 =  27  : 6 : 1

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