Questions
A massless rod S having length 2l has equal point masses attached to its two ends as shown in figure. The rod is rotating about an axis passing through its centre and making an angle with the axis. The magnitude of change of angular momentum of rod equals [AIIMS 2015]
detailed solution
Correct option is B
The radius of the circle followed by the masses, r=lsinαAs, angular momentum, L=r×p=r×mv⇒ |L|=lsinα(mωlsinα)On differentiating both sides, we get d|L|dt=mωl22sinα⋅cosαdαdt⇒ dLdt=2ml2ω2sinα⋅cosα=ml2ω2sin2αTalk to our academic expert!
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A disc can rotate about an axis passing through its centre and perpendicular to the plane of the disc. Initially the disc is stationary and its moment of inertia about the axis is 4 Kg-m2. A torque is applied on the disc which varies with time according to the graph shown in figure. Then angular velocity of the disc at the end of 6th second is
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