Match the Column I with Column II and select the option from the given code below
Codes
i-p ii-q iii-r iv-s
i-q ii-p iii-s iv -r
i-p ii-r iii-s iv - r
i - s ii- r iii- q iv- p
(i) 2i^×i^+j^ = 2i^×i^+2i^×j^ = 2k^
(ii) 4i^×2i^−j^ = 4i^×2i^−4i^×j^ = 0−4k^ =−4k^
(iii) 3i^×3i^−4j^ = 3i^×3i^−12(i^×j^) = 0−12k^ =−12k^
(iv) 2i^+j^×2i^ = 4(i^×j^)i+4(j^×i^) = 0+(−4k^) =−4k^
Hence, (i)→ (p), (ii) → (r) , (iii) →(s), (iv)→(r)