First slide
Vectors
Question

Match the Column I with Column II and select the option from the given code below

 Column I Column II
i.2i^×i^+j^p.2k^
ii.4i^×2i^j^q.0
iii.3i^×3i^4j^r.4k^
iv.2i^+j^×2i^s.12k^

Codes

Moderate
Solution

(i) 2i^×i^+j^=2i^×i^+2i^×j^=2k^

(ii) 4i^×2i^j^=4i^×2i^4i^×j^=04k^=4k^

(iii) 3i^×3i^4j^=3i^×3i^12(i^×j^)=012k^=12k^

(iv) 2i^+j^×2i^=4(i^×j^)i+4(j^×i^)=0+(4k^)=4k^

Hence, (i) (p), (ii)  (r) ,  (iii) (s), (iv)(r) 

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