Questions
Match the following in List - I and List - II For a projectile (R = Range, H = Maximum height, = angle of projection, T = time of flight)
| List – I | List – II | ||
| a) | For height to become maximum | e) | 45° |
| b) | For Maximum Range | f) | tan-1 (4) |
| c) | For R = H | g) | tan-1 (2) |
| d) | For gT2 = 4R | h) | 90° |
| a | b | c | d | |
| 1 | h | e | f | g |
| 2 | f | e | h | g |
| 3 | h | f | g | e |
| 4 | f | h | e | g |
detailed solution
Correct option is A
(1) Maximum Height H=U2sin2θ2gθ=90∘ H is maximum (h)(2) Range =U2sin2θg when θ 45° R is maximum (e)(3) θ=45∘R=U2sin2sinθcosθg; =H=U2sin2θ2g if H=R tanθ=4(f)(4) gT2=4R;g⋅2Usinθg2=4U2sin2sinθcosθg ; tanθ= 2Talk to our academic expert!
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