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The maximum acceleration or deceleration that a train may have is a = 5 ms-2. The minimum time in which the train may reach from one station to the other separated by a distance d=500 m is t0=5 n s. The value of n is ________.

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answer is 4.

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Detailed Solution

From the graph,d=12×v0t0=v0t02 and tan⁡θ=a=v0t0/2=2v0t0∴v0=at02∴d=t02×at02=at024∴t0=2da=25005=20s=20=5n∴n=4

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The maximum acceleration or deceleration that a train may have is a = 5 ms-2. The minimum time in which the train may reach from one station to the other separated by a distance d=500 m is t0=5 n s. The value of n is ________.